5x^2=57+4x

Solution for 5x^2=57+4x equation:

5x^2=57+4x

We move all terms to the left:

5x^2-(57+4x)=0

We add all the numbers together, and all the variables

5x^2-(4x+57)=0

We get rid of parentheses

5x^2-4x-57=0

a = 5; b = -4; c = -57;
Δ = b2-4ac
Δ = -42-4·5·(-57)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-34}{2*5}=\frac{-30}{10}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+34}{2*5}=\frac{38}{10}
=3+4/5
$